For the reaction , the correct statement(s) is/are: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1:** Reduction: $ClO_3^- + 6H^+ + 6e^- \rightarrow Cl^- + 3H_2O$. <br>**Step 2:** Oxidation: $2I^- \rightarrow I_2 + 2e^-$. <br>**Step 3:** To balance $e^-$, multiply oxidation by 3. <br>**Net:** $ClO_3^- + 6I^- + 6H^+ \rightarrow Cl^- + 3I_2 + 3H_2O$. <br>**Step 4:** Since the medium is $H_2SO_4$ (forming $HSO_4^-$), $6H^+$ comes from $6H_2SO_4$. <br>**Final:** $6I^- + ClO_3^- + 6H_2SO_4 \rightarrow 3I_2 + Cl^- + 6HSO_4^- + 3H_2O$. <br>Coefficients: $HSO_4^-$ is 6 (A). $I$ goes from -1 to 0 (B). $S$ remains +6 (C is false). $H_2O$ is produced (D).