In the reaction , which of the following is/are correct? — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1:** Balance using O.S. method. $I$ goes from -1 to 0 ($\Delta = 1$). $N$ goes from +5 to +2 ($\Delta = 3$). <br>**Step 2:** Multiply $I$ by 3 and $N$ by 1. For $I_2$, we need 6 $HI$. <br>**Balanced:** $6HI + 2HNO_3 \rightarrow 2NO + 3I_2 + 4H_2O$. Thus $x=6, y=2$. <br>**Step 3:** Nitrogen is reduced, so $NO$ is the reduction product. Iodine is oxidized, so $I_2$ is the oxidation product. [2]