The oxidation state of in is: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Redox Reactions and Volumetric AnalysismediumINTEGER

Question

The oxidation state of $O$ in $F_2O$ is:

Answer: 2

💡 Solution & Explanation

Fluorine is the most electronegative element (-1). <br>Calculation: $2(-1) + x = 0 \Rightarrow x = +2$.

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