-factor of as an oxidizing agent when it is reduced to is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
$n$-factor of $Fe_2(SO_4)_3$ as an oxidizing agent when it is reduced to $FeSO_4$ is:
Answer: 2
💡 Solution & Explanation
**Step 1:** $Fe_2(SO_4)_3 \rightarrow 2FeSO_4$. <br>**Step 2:** $Fe$ goes from +3 to +2. Change per atom = 1. <br>**Step 3:** Since there are 2 $Fe$ atoms per molecule, the total electrons gained ($n$-factor) = 2.
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