Oxidation number of in is: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Redox Reactions and Volumetric AnalysismediumINTEGER

Question

Oxidation number of $P$ in $H_4P_2O_7$ is:

Answer: 5

💡 Solution & Explanation

Calculation: $4(+1) + 2x + 7(-2) = 0 \Rightarrow 4 + 2x - 14 = 0 \Rightarrow 2x = 10 \Rightarrow x = +5$.

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