Oxidation number of in is: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Redox Reactions and Volumetric AnalysismediumINTEGER

Question

Oxidation number of $P$ in $H_4P_2O_7$ is:

Answer: 5

💡 Solution & Explanation

Calculation: $4(+1) + 2x + 7(-2) = 0 \Rightarrow 4 + 2x - 14 = 0 \Rightarrow 2x = 10 \Rightarrow x = +5$.

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry