Oxidation number of in is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
Oxidation number of $P$ in $H_4P_2O_7$ is:
Answer: 5
💡 Solution & Explanation
Calculation: $4(+1) + 2x + 7(-2) = 0 \Rightarrow 4 + 2x - 14 = 0 \Rightarrow 2x = 10 \Rightarrow x = +5$.
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