mL of (as a reducing agent) requires mL of in acidic medium. The value of is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
$100$ mL of $0.1 M$ $KHC_2O_4.H_2C_2O_4$ (as a reducing agent) requires $x$ mL of $0.1 M$ $KMnO_4$ in acidic medium. The value of $x$ is:
Answer: 80
💡 Solution & Explanation
**Step 1:** The salt has 2 oxalate units. $n$-factor = 4 ($2 \times 2$). <br>**Step 2:** Meq of salt = $100 \times 0.1 \times 4 = 40$. <br>**Step 3:** Meq of $KMnO_4 = x \times 0.1 \times 5 = 0.5x$. <br>**Step 4:** $0.5x = 40 \Rightarrow x = 80$ mL.
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