-factor of in the reaction is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
$n$-factor of $KIO_3$ in the reaction $2IO_3^- + 5SO_2 + 4H_2O \rightarrow I_2 + 5SO_4^{2-} + 8H^+$ is:
Answer: 5
💡 Solution & Explanation
In $IO_3^-$, iodine is in $+5$ state. In $I_2$, it is in $0$ state. <br>The change in oxidation state per iodine atom is 5. <br>Thus, $n$-factor for $KIO_3$ is 5.
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