The sum of the oxidation states of all Nitrogen atoms in is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1:** In $NH_4^+$, $x + 4(+1) = +1 \Rightarrow x = -3$. <br>**Step 2:** In $NO_2^-$, $y + 2(-2) = -1 \Rightarrow y = +3$. <br>**Step 3:** Sum = $(-3) + (+3) = 0$. (Wait, usually questions ask for absolute values or specific atoms. If the question asks for the sum of magnitudes: $3+3=6$. Following standard O.S. logic, the sum is 0. If "sum of oxidation states" refers to formal O.S., it is 0).