Volume of (in mL) needed to oxidize mL of is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
Volume of $0.1 N$ $KMnO_4$ (in mL) needed to oxidize $100$ mL of $0.1 N$ $FeSO_4$ is:
Answer: 100
💡 Solution & Explanation
In terms of normality, the reaction is $1:1$ equivalent wise. <br>$N_1 V_1 = N_2 V_2 \Rightarrow 0.1 \times V = 0.1 \times 100 \Rightarrow V = 100$ mL.
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