In (potassium superoxide), the oxidation state of oxygen is . Find : — Redox Reactions and Volumetric Analysis Chemistry Question
Question
In $KO_2$ (potassium superoxide), the oxidation state of oxygen is $-1/x$. Find $x$:
Answer: 2
💡 Solution & Explanation
Potassium is +1. <br>Calculation: $1 + 2x = 0 \Rightarrow 2x = -1 \Rightarrow x = -1/2$. <br>Comparing to $-1/x$, the value of $x$ is 2.
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