mL of is required to neutralize mL of . is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
$25$ mL of $0.1 N$ $NaOH$ is required to neutralize $V$ mL of $0.5 N$ $HCl$. $V$ is:
Answer: 5
💡 Solution & Explanation
Using normality equation: $N_1 V_1 = N_2 V_2$. <br>$0.1 \times 25 = 0.5 \times V \Rightarrow 2.5 = 0.5 V \Rightarrow V = 5$ mL.
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