One mole of loses 10 moles of electrons to form a new compound . The oxidation state of in is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
One mole of $N_2H_4$ loses 10 moles of electrons to form a new compound $Y$. The oxidation state of $N$ in $Y$ is:
Answer: 3
💡 Solution & Explanation
Initial O.S. in $N_2H_4$ is -2. <br>Total 10e- loss for 2 $N$ atoms = 5e- loss per $N$ atom. <br>New O.S. = $(\text{Initial O.S.}) + (\text{Change}) = -2 + 5 = +3$.
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