mL of is equivalent to mL of . The value of is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
$10$ mL of $0.1 M$ $K_2Cr_2O_7$ is equivalent to $V$ mL of $0.6 M$ $FeSO_4$. The value of $V$ is:
Answer: 10
💡 Solution & Explanation
Meq of $K_2Cr_2O_7 = 10 \times 0.1 \times 6 = 6$. <br>Meq of $FeSO_4 = V \times 0.6 \times 1 = 0.6V$. <br>Equating: $0.6V = 6 \Rightarrow V = 10$ mL.
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