mL of is equivalent to mL of . The value of is: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Question

$10$ mL of $0.1 M$ $K_2Cr_2O_7$ is equivalent to $V$ mL of $0.6 M$ $FeSO_4$. The value of $V$ is:

Answer: 10

💡 Solution & Explanation

Meq of $K_2Cr_2O_7 = 10 \times 0.1 \times 6 = 6$. <br>Meq of $FeSO_4 = V \times 0.6 \times 1 = 0.6V$. <br>Equating: $0.6V = 6 \Rightarrow V = 10$ mL.

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes