-factor of in the reaction is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
$n$-factor of $S_2O_3^{2-}$ in the reaction $S_2O_3^{2-} + I_2 \rightarrow S_4O_6^{2-} + I^-$ is:
Answer: 1
💡 Solution & Explanation
In the reaction, $S$ in $S_2O_3^{2-}$ (+2) goes to $S$ in $S_4O_6^{2-}$ (+2.5). <br>Change in O.S. per $S$ atom = $0.5$. <br>Number of $S$ atoms in $S_2O_3^{2-}$ = 2. <br>Total electrons lost per molecule ($n$-factor) = $2 \times 0.5 = 1$.
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