Oxidation number of in is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
Oxidation number of $Cr$ in $[Cr(H_2O)_4Cl_2]Cl$ is:
Answer: 3
💡 Solution & Explanation
In the complex $[Cr(H_2O)_4Cl_2]^+$, $H_2O$ is a neutral ligand ($0$) and $Cl$ is $-1$. <br>Let $Cr$ be $x$: $x + 4(0) + 2(-1) = +1$ (net charge of coordination sphere). <br>$x - 2 = 1 \Rightarrow x = +3$.
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