The number of moles of required to oxidize moles of in acidic medium is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1:** $n$-factor of $KMnO_4$ in acidic medium = 5. <br>**Step 2:** $n$-factor of $FeSO_4$ ($Fe^{2+} \rightarrow Fe^{3+}$) = 1. <br>**Step 3:** Equating equivalents: $5 \times (\text{moles of } KMnO_4) = 1 \times 5 \text{ moles of } FeSO_4$. <br>**Step 4:** Moles of $KMnO_4 = 5/5 = 1$.