The oxidation state of sulfur in (Sodium tetrathionate) is . The value of is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
The oxidation state of sulfur in $Na_2S_4O_6$ (Sodium tetrathionate) is $x.y$. The value of $(x+y)$ is:
Answer: 7
💡 Solution & Explanation
**Step 1:** Calculation for average O.S.: $2(+1) + 4x + 6(-2) = 0 \Rightarrow 2 + 4x - 12 = 0 \Rightarrow 4x = 10 \Rightarrow x = 2.5$. <br>**Step 2:** Here $x=2$ and $y=5$. <br>**Step 3:** $(x+y) = 2+5 = 7$.
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