-factor of when it is oxidized to and is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
$n$-factor of $Cu_2S$ when it is oxidized to $Cu^{2+}$ and $SO_2$ is:
Answer: 8
💡 Solution & Explanation
**Step 1:** $Cu_2S \rightarrow 2Cu^{2+} + SO_2$. <br>**Step 2:** Oxidation of Copper: $2Cu^+ \rightarrow 2Cu^{2+} + 2e^-$ (1 electron per $Cu$). <br>**Step 3:** Oxidation of Sulfur: $S^{2-} \rightarrow S^{4+} + 6e^-$. <br>**Step 4:** Total electrons lost per formula unit = $2 + 6 = 8$.
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