The number of moles of required to oxidize 1 mole of in acidic medium is . The value of is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

$n$-factor of $K_2Cr_2O_7 = 6$. $n$-factor of $Fe^{2+} = 1$. <br>Equivalents must be equal: $6 \times \text{moles}(K_2Cr_2O_7) = 1 \times 1 \text{ mole } Fe^{2+}$. <br>Moles = 1/6. Comparing with $1/n$, $n=6$.