In the balanced reaction , the value of is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
In the balanced reaction $xI^- + yClO_3^- + 6H_2SO_4 \rightarrow Cl^- + 3I_2 + 6HSO_4^- + 3H_2O$, the value of $x$ is:
Answer: 6
💡 Solution & Explanation
**1.** Reduction: $ClO_3^-$ (+5) to $Cl^-$ (-1) gains $6e^-$. <br>**2.** Oxidation: $2I^-$ to $I_2$ loses $2e^-$. <br>**3.** To balance electrons, multiply oxidation half by 3: $6I^- \rightarrow 3I_2 + 6e^-$. <br>Thus, the coefficient $x$ for $I^-$ is 6.
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