The oxidation state of in is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
The oxidation state of $Cr$ in $K_3CrO_8$ is:
Answer: 5
💡 Solution & Explanation
$K_3CrO_8$ is a tetraperoxo complex $[Cr(O_2)_4]^{3-}$. Each peroxo group ($O_2^{2-}$) has an O.S. of -2. <br>Calculation: $3(+1) + x + 4(-2) = 0 \Rightarrow 3 + x - 8 = 0 \Rightarrow x = +5$.
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