moles of is oxidized to by moles of in acidic medium. The value of is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1:** $n$-factor $H_2SO_3 \rightarrow H_2SO_4$ is 2 ($S$: +4 to +6). <br>**Step 2:** $n$-factor $K_2Cr_2O_7 \rightarrow 2Cr^{3+}$ is 6. <br>**Step 3:** Eq $H_2SO_3$ = Eq $K_2Cr_2O_7 \Rightarrow 0.5 \times 2 = x \times 6$. <br>$1 = 6x \Rightarrow x = 1/6$. <br>**Final:** $12x = 12(1/6) = 2$.