Oxidation state of iron in the brown ring complex is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

In this complex, $NO$ transfers an electron to $Fe^{2+}$ to become $NO^+$ and $Fe^+$. <br>Calculation: $x (\text{Fe}) + 5(0) (\text{H}_2\text{O}) + 1 (+1) (\text{NO}^+) = +2 (\text{complex ion charge})$. <br>$x + 1 = 2 \Rightarrow x = +1$.