The number of moles of required to oxidize one mole of in acidic medium is (in simplest fraction for — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1:** $n$-factor of $KMnO_4$ (acidic) = 5. <br>**Step 2:** $n$-factor of $FeC_2O_4 = 3$ ($Fe^{2+} \rightarrow Fe^{3+}$ is 1; $C_2O_4^{2-} \rightarrow 2CO_2$ is 2). <br>**Step 3:** Equating equivalents: $5 \times n_{KMnO_4} = 3 \times 1 \text{ mole}$. <br>$n_{KMnO_4} = 3/5$. Here $x=3, y=5$. <br>**Final:** $x+y = 3+5 = 8$.