The oxidation number of sulfur in Marshall's acid () is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Marshall's acid contains one peroxide linkage ($-O-O-$). The structure is $HO-SO_2-O-O-SO_2-OH$. <br>Calculation: $2(+1) + 2(x) + 6(-2) \text{ [oxo]} + 2(-1) \text{ [peroxo]} = 0$. <br>$2 + 2x - 12 - 2 = 0 \Rightarrow 2x = 12 \Rightarrow x = +6$.