**Passage 13 (continued):** <br> **Q2:** The total moles of required in the second titration is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1:** After first titration, all iron is $Fe^{3+}$ (Total $0.2$ moles). <br>**Step 2:** $Zn/HCl$ reduces all $Fe^{3+}$ back to $Fe^{2+}$. <br>**Step 3:** Moles $KMnO_4$ for $0.2$ moles $Fe^{2+} = 0.2 / 5 = 0.04$ moles.