**Passage 11 (continued):** **Q2:** The percentage of silver in the alloy is ($Mw$ of $Ag = 108$):

Correct answer: A. **Step 1:** Moles = . **Step 2:** Moles = Moles = . **Step 3:** Mass g. **Step 4:** Ag = .

**Passage 11 (continued):** **Q2:** The percentage of silver in the alloy is ( of ): | Redox Reactions and Volumetric Analysis — Chem-Mantra

Question

**Passage 11 (continued):** **Q2:** The percentage of silver in the alloy is ($Mw$ of $Ag = 108$):

Answer: A

💡 Solution & Explanation

**Step 1:** Moles $SCN^-$ = $25 \times 0.1 / 1000 = 0.0025$. **Step 2:** Moles $Ag^+$ = Moles $SCN^-$ = $0.0025$. **Step 3:** Mass $Ag = 0.0025 \times 108 = 0.27$ g. **Step 4:** $\%$ Ag = $(0.27 / 2.0) \times 100 = 13.5\%$.

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💡 Solution & Explanation

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