**Passage 10 (continued):** <br> **Q2:** The percentage of nitrogen in the compound is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1:** Meq of acid reacted with $NH_3$ = $(\text{Initial Meq}) - (\text{Meq of NaOH used for residual})$. <br>**Step 2:** Meq reacted = $50 - (60 \times 0.5 \times 1) = 50 - 30 = 20$. <br>**Step 3:** $\%$ N = $(1.4 \times \text{Meq reacted}) / \text{mass of compound}$. <br>**Step 4:** $\%$ N = $(1.4 \times 20) / 0.5 = 28 / 0.5 = 56\%$.