Redox Reactions and Volumetric AnalysishardCOMPREHENSIVE

**Passage 9 (continued):** <br> **Q2:** The mass of sulfur produced in the second step is:Redox Reactions and Volumetric Analysis Chemistry Question

Question

**Passage 9 (continued):** <br> **Q2:** The mass of sulfur produced in the second step is:

Answer: A

💡 Solution & Explanation

**Step 1:** $2H_2S + O_2 \rightarrow 2S + 2H_2O$. <br>**Step 2:** $1$ mole $O_2$ produces $2$ moles $S$. <br>**Step 3:** $0.3$ moles $O_2$ produces $0.6$ moles $S$. <br>**Step 4:** Mass $S = 0.6 \times 32 = 19.2$ g.

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