**Passage 9 (continued):** <br> **Q2:** The mass of sulfur produced in the second step is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**Passage 9 (continued):** <br> **Q2:** The mass of sulfur produced in the second step is:
Answer: A
💡 Solution & Explanation
**Step 1:** $2H_2S + O_2 \rightarrow 2S + 2H_2O$. <br>**Step 2:** $1$ mole $O_2$ produces $2$ moles $S$. <br>**Step 3:** $0.3$ moles $O_2$ produces $0.6$ moles $S$. <br>**Step 4:** Mass $S = 0.6 \times 32 = 19.2$ g.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes