**Passage 8:** A mixture of and requires mL of for titration in acidic medium. The same amount of mi — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**Passage 8:** A mixture of $FeC_2O_4$ and $Fe_2(C_2O_4)_3$ requires $50$ mL of $0.1 M$ $KMnO_4$ for titration in acidic medium. The same amount of mixture requires $40$ mL of $0.1 M$ $NaOH$ for complete neutralization. <br> **Q1:** The moles of $Fe_2(C_2O_4)_3$ in the mixture is:
💡 Solution & Explanation
**Step 1:** Let moles be $x$ and $y$. <br>**Step 2:** Acid-Base: $Fe_2(C_2O_4)_3$ is not acidic, but the question assumes hydrolysis or specific acidic units. Usually, only the oxalate moiety reacts with $KMnO_4$. <br>**Step 3:** $n$-factor $FeC_2O_4 = 3$; $n$-factor $Fe_2(C_2O_4)_3 = 6$. <br>**Step 4:** $3x + 6y = 50 \times 0.1 \times 5 = 25$ meq. (Solving system yields $y=0.0005$).