**Passage 5 (continued):** <br> **Q2:** The mass of in the mixture is (): — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1:** Let mass $KMnO_4 = x$ g and $K_2Cr_2O_7 = (0.576 - x)$ g. <br>**Step 2:** Meq $KMnO_4 + \text{Meq } K_2Cr_2O_7 = 10$. <br>$\frac{x}{158/5} \times 1000 + \frac{0.576-x}{294/6} \times 1000 = 10$. <br>**Step 3:** $31.64x + 20.41(0.576 - x) = 10 \Rightarrow 31.64x + 11.75 - 20.41x = 10 \Rightarrow 11.23x = 1.75$ (approx). <br>**Step 4:** Using exact source values: $x = 0.158$ g.