**Passage 4 (continued):** **Q2:** Moles of $KMnO_4$ required to oxidize 1 mole of $K_4[Fe(CN)_6]$ is:

Correct answer: A. **Step 1:** . **Step 2:** . **Step 3:** Moles .

**Passage 4 (continued):** <br> **Q2:** Moles of required to oxidize 1 mole of is: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Question

**Passage 4 (continued):** <br> **Q2:** Moles of $KMnO_4$ required to oxidize 1 mole of $K_4[Fe(CN)_6]$ is:

Answer: A

💡 Solution & Explanation

**Step 1:** $n_1 M_1 = n_2 M_2$. <br>**Step 2:** $5 \times \text{moles } KMnO_4 = 61 \times 1 \text{ mole } K_4[Fe(CN)_6]$. <br>**Step 3:** Moles $KMnO_4 = 61 / 5 = 12.2$.

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💡 Solution & Explanation

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