**Passage 4:** The reaction between and in acidic medium results in and . <br> **Q1:** The -factor o — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**Passage 4:** The reaction between $K_4[Fe(CN)_6]$ and $KMnO_4$ in acidic medium results in $Fe^{3+}, CO_2$ and $NO_3^-$. <br> **Q1:** The $n$-factor of $K_4[Fe(CN)_6]$ is:
Answer: C
💡 Solution & Explanation
**Step 1:** $Fe^{2+} \rightarrow Fe^{3+}$ ($1 e^-$). <br>**Step 2:** $6C^{2+} \rightarrow 6C^{4+}$ ($12 e^-$). <br>**Step 3:** $6N^{3-} \rightarrow 6N^{5+}$ ($48 e^-$). <br>**Step 4:** Total electrons lost = $1 + 12 + 48 = 61$.
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