Redox Reactions and Volumetric AnalysishardCOMPREHENSIVE

**Passage 3:** A g sample of copper ore is dissolved and treated with excess . The liberated requireRedox Reactions and Volumetric Analysis Chemistry Question

Question

**Passage 3:** A $0.5$ g sample of copper ore is dissolved and treated with excess $KI$. The liberated $I_2$ requires $20$ mL of $0.1 M$ $Na_2S_2O_3$ for titration. <br> **Q1:** The moles of $I_2$ liberated is:

Answer: A

💡 Solution & Explanation

**Step 1:** $2Cu^{2+} + 4I^- \rightarrow Cu_2I_2 + I_2$. <br>**Step 2:** $I_2 + 2S_2O_3^{2-} \rightarrow 2I^- + S_4O_6^{2-}$. <br>**Step 3:** Meq $Na_2S_2O_3 = 20 \times 0.1 = 2$. <br>**Step 4:** Moles $Na_2S_2O_3 = 2 / 1000 = 0.002$. <br>**Step 5:** Stoichiometry: 1 mole $I_2 \equiv 2$ moles Hypo. <br>**Step 6:** Moles $I_2 = 0.002 / 2 = 0.001$.

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