Redox Reactions and Volumetric AnalysishardCOMPREHENSIVE

**Passage 1 (continued):** <br> **Q3:** mL of vol is mixed with mL of vol . The volume strength of tRedox Reactions and Volumetric Analysis Chemistry Question

Question

**Passage 1 (continued):** <br> **Q3:** $20$ mL of $10$ vol $H_2O_2$ is mixed with $50$ mL of $20$ vol $H_2O_2$. The volume strength of the resulting solution is:

Answer: B

💡 Solution & Explanation

**Step 1:** Calculate total $O_2$ available. <br>From sol. 1: $20 \times 10 = 200$ mL $O_2$. <br>From sol. 2: $50 \times 20 = 1000$ mL $O_2$. <br>**Step 2:** Total $O_2 = 1200$ mL. <br>**Step 3:** Total volume of solution = $20 + 50 = 70$ mL. <br>**Step 4:** Resulting Vol. Strength = $1200 / 70 = 17.14$.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry