Redox Reactions and Volumetric AnalysishardCOMPREHENSIVE

**Passage 1 (continued):** <br> **Q2:** The molarity of 11.2 vol solution is:Redox Reactions and Volumetric Analysis Chemistry Question

Question

**Passage 1 (continued):** <br> **Q2:** The molarity of 11.2 vol $H_2O_2$ solution is:

Answer: A

💡 Solution & Explanation

**Step 1:** Relation between Volume Strength and Molarity: $\text{Vol. Strength} = 11.2 \times M$. <br>**Step 2:** $11.2 = 11.2 \times M \Rightarrow M = 1 M$. (Alternatively, $M = N/2 = 2/2 = 1 M$).

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry