**(A):** The oxidation state of in is +2. <br> **(R):** Fluorine is more electronegative than Oxygen — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**(A):** The oxidation state of $O$ in $OF_2$ is +2. <br> **(R):** Fluorine is more electronegative than Oxygen.
Answer: A
💡 Solution & Explanation
**Assertion:** Calculation: $x + 2(-1) = 0 \Rightarrow x = +2$. Statement is true. <br>**Reason:** Because $F$ is the most electronegative element, it is assigned the negative O.S. (-1). Oxygen, being less electronegative than Fluorine, must take a positive O.S. to balance the molecule.
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