**(A):** is a non-stoichiometric compound. <br> **(R):** It contains and in a specific ratio to main — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**(A):** $Fe_{0.94}O$ is a non-stoichiometric compound. <br> **(R):** It contains $Fe^{2+}$ and $Fe^{3+}$ in a specific ratio to maintain charge neutrality.
Answer: A
💡 Solution & Explanation
**Assertion:** The metal-to-oxygen ratio is not a simple whole number, which is the definition of a non-stoichiometric compound. Statement is true. <br>**Reason:** In the crystal lattice, some $Fe^{2+}$ ions are missing. To maintain electrical neutrality, two $Fe^{3+}$ ions are present for every missing $Fe^{2+}$. This creates the observed non-stoichiometry.
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