**(A):** A solution of is . <br> **(R):** Normality = Molarity -factor. — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**(A):** A $1.0 N$ solution of $H_2SO_4$ is $0.5 M$. <br> **(R):** Normality = Molarity $\times$ $n$-factor.
Answer: A
💡 Solution & Explanation
**Assertion:** For $H_2SO_4$, the $n$-factor (basicity) is 2. $M = N/n = 1.0/2 = 0.5 M$. Statement is true. <br>**Reason:** The formula $N = M \times n$ is the fundamental relationship between normality and molarity. It correctly explains the calculation in the assertion.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes