**(A):** The average oxidation state of Sulfur in is +2.5. <br> **(R):** In the tetrathionate ion, t — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**(A):** The average oxidation state of Sulfur in $Na_2S_4O_6$ is +2.5. <br> **(R):** In the tetrathionate ion, two sulfur atoms have O.S. of +5 and two have O.S. of 0.
Answer: A
💡 Solution & Explanation
**Assertion:** $2(+1) + 4x + 6(-2) = 0 \Rightarrow 4x = 10 \Rightarrow x = +2.5$. [8], [9] <br>**Reason:** The structure is $^-O_3S-S-S-SO_3^-$. The terminal sulfurs are +5 and the central ones in the chain are 0. Average = $(5+0+0+5)/4 = 2.5$. [9]
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