**(A):** The -factor of is 1 when it reacts with . <br> **(R):** In this reaction, two moles of lose — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**(A):** The $n$-factor of $Na_2S_2O_3$ is 1 when it reacts with $I_2$. <br> **(R):** In this reaction, two moles of $Na_2S_2O_3$ lose two moles of electrons to form one mole of $Na_2S_4O_6$.
Answer: A
💡 Solution & Explanation
**Assertion:** Reaction: $2S_2O_3^{2-} + I_2 \rightarrow S_4O_6^{2-} + 2I^-$. The change in O.S. per sulfur is 0.5; for two sulfurs, it is 1. [6], [7] <br>**Reason:** The stoichiometry shows 1 electron is lost per $S_2O_3^{2-}$ unit, which correctly explains the $n$-factor of 1. [7]
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