**(A):** In acidic medium, is a more powerful oxidizing agent than in neutral medium. <br> **(R):** — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**(A):** In acidic medium, $KMnO_4$ is a more powerful oxidizing agent than in neutral medium. <br> **(R):** The reduction potential of $MnO_4^-$ depends on the concentration of $H^+$ ions.
Answer: A
💡 Solution & Explanation
**Assertion:** $E^o$ for $MnO_4^-/Mn^{2+}$ (+1.51V) is higher than for $MnO_4^-/MnO_2$ (+1.23V). True. <br>**Reason:** According to Nernst equation for $MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$, $E$ increases as $[H^+]$ increases. True and explains why it's stronger in acid.
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