**(A):** The oxidation state of Chromium in is +6. <br> **(R):** has a butterfly structure with two — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Assertion:** In $CrO_5$, one oxygen is $O^{2-}$ and four are $O^{-1}$ (peroxides). $x + 1(-2) + 4(-1) = 0 \Rightarrow x = +6$. True. <br>**Reason:** The butterfly structure contains two peroxo ($O-O$) linkages which accounts for the four $O^{-1}$ atoms. True and explains the O.S.