**Match the mixture properties (Average Molecular Weight ):** <br><br>**Column I:** <br>(A) and ( mo — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
**Match the mixture properties (Average Molecular Weight $M_{avg}$):** <br><br>**Column I:** <br>(A) $He$ and $CH_4$ ($1:1$ mole ratio) <br>(B) $H_2$ and $He$ ($1:1$ mole ratio) <br>(C) $O_2$ and $SO_2$ ($1:1$ mole ratio) <br>(D) $N_2$ and $CO$ (any ratio) <br><br>**Column II:** <br>(P) $M_{avg} = 28$ <br>(Q) $M_{avg} = 10$ <br>(R) $M_{avg} = 3$ <br>(S) $M_{avg} = 48$
Answer: (A) $\RIGHTARROW$ Q <BR>(B) $\RIGHTARROW$ R <BR>(C) $\RIGHTARROW$ S <BR>(D) $\RIGHTARROW$ P
💡 Solution & Explanation
**(A)** $(4+16)/2 = 10$ (Q). <br>**(B)** $(2+4)/2 = 3$ (R). <br>**(C)** $(32+64)/2 = 48$ (S). <br>**(D)** Since both $N_2$ and $CO$ are $28$, any mixture will have $M_{avg} = 28$ (P).
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes