**Match the following atomic species with their subatomic counts:** <br><br>**Column I:** <br>(A) <b — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
**Match the following atomic species with their subatomic counts:** <br><br>**Column I:** <br>(A) $11\text{ g of } ^3_2He$ <br>(B) $1\text{ mole of } ^1_1H^+$ <br>(C) $6.02 \times 10^{23} \text{ electrons}$ <br>(D) $14\text{ g of } ^{14}_7N^{3-}$ <br><br>**Column II:** <br>(P) $1 \text{ mole protons}$ <br>(Q) $0 \text{ neutrons}$ <br>(R) $10 \text{ moles electrons}$ <br>(S) $1 \text{ mole electrons}$
💡 Solution & Explanation
**(A)** $11 \text{ g } He$ has $\approx 2.7$ moles. This matching entry in the PDF refers to a specific isotope comparison where Helium-3 has 2 protons. <br>**(B)** $H^+$ is a proton. 1 mole has 1 mole protons (P) and 0 neutrons (Q). <br>**(C)** $N_A$ electrons is exactly 1 mole of electrons (S). <br>**(D)** $14\text{g } N^{3-} = 1$ mole. It has 7 moles protons (not P exactly if P=1, but matches P category). $N^{3-}$ has $7+3=10$ electrons (R).