of a mixture of and is heated. The weight of the residue is . The percentage of in the mixture is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

Let $x$ be mass of $CaCO_3$. Moles $CO_2 = x/100 + (10-x)/197$. <br>Mass loss ($CO_2$) $= 10 - 6.15 = 3.85\text{ g}$. <br>$(x/100 + (10-x)/197) \times 44 = 3.85$. Solving for $x$ gives approximately $5.0\text{ g}$, which is 50%.