To of , of is added. The final molarity of in the mixture is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
To $100 \text{ mL}$ of $0.1 \text{ M } HCl$, $100 \text{ mL}$ of $0.2 \text{ M } NaOH$ is added. The final molarity of $OH^-$ in the mixture is:
Answer: A
💡 Solution & Explanation
$\text{mEq } H^+ = 100 \times 0.1 = 10$. <br>$\text{mEq } OH^- = 100 \times 0.2 = 20$. <br>$\text{Excess } OH^- = 20 - 10 = 10 \text{ mEq}$. <br>$\text{Total volume} = 200 \text{ mL}$. <br>$\text{Molarity } [OH^-] = 10 / 200 = 0.05 \text{ M}$.
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