What is the weight of (MW=294) required to prepare of solution for use as an oxidizing agent in acid — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
What is the weight of $K_2Cr_2O_7$ (MW=294) required to prepare $250 \text{ mL}$ of $0.1 \text{ N}$ solution for use as an oxidizing agent in acidic medium?
Answer: A
💡 Solution & Explanation
n-factor $= 6$. $\text{Eq. wt} = 294 / 6 = 49$. $\text{Mass} = N \times V(L) \times \text{Eq. wt} = 0.1 \times 0.25 \times 49 = 1.225 \text{ g}$.
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