10 g of on heating gives 0.1 mole of and 4g of . This data illustrates: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
10 g of $MgCO_3$ on heating gives 0.1 mole of $CO_2$ and 4g of $MgO$. This data illustrates:
Answer: A
💡 Solution & Explanation
Reactant $= 10\text{g}$. Products $= (0.1 \times 44) + 4 = 4.4 + 4 = 8.4\text{g}$. (Implicitly assuming remainder is impurity or the system is closed/open, but typically used to verify mass balance in stoichiometry problems).
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