The molarity of in a solution containing 5.85g and 11.1g in 500 mL is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
The molarity of $Cl^-$ in a solution containing 5.85g $NaCl$ and 11.1g $CaCl_2$ in 500 mL is:
Answer: B
💡 Solution & Explanation
$\text{Moles } Cl^- \text{ from } NaCl = 0.1$; from $CaCl_2 = 2 \times (11.1/111) = 0.2$. Total moles $= 0.3$. $\text{Molarity} = 0.3 / 0.5 = 0.6 \text{ M}$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes